6n^2+18n-60=0

Solution for 6n^2+18n-60=0 equation:

6n^2+18n-60=0

a = 6; b = 18; c = -60;
Δ = b2-4ac
Δ = 182-4·6·(-60)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-42}{2*6}=\frac{-60}{12}
=-5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+42}{2*6}=\frac{24}{12}
=2
$